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X=-2X^2-4X^2-8X-10X+96
We move all terms to the left:
X-(-2X^2-4X^2-8X-10X+96)=0
We get rid of parentheses
2X^2+4X^2+8X+10X+X-96=0
We add all the numbers together, and all the variables
6X^2+19X-96=0
a = 6; b = 19; c = -96;
Δ = b2-4ac
Δ = 192-4·6·(-96)
Δ = 2665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{2665}}{2*6}=\frac{-19-\sqrt{2665}}{12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{2665}}{2*6}=\frac{-19+\sqrt{2665}}{12} $
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