X=-4(x+3)(x+4)

Solution for X=-4(x+3)(x+4) equation:

X=-4(X+3)(X+4)

We move all terms to the left:

X-(-4(X+3)(X+4))=0

We multiply parentheses ..

-(-4(+X^2+4X+3X+12))+X=0


We calculate terms in parentheses: -(-4(+X^2+4X+3X+12)), so:

-4(+X^2+4X+3X+12)

We multiply parentheses

-4X^2-16X-12X-48

We add all the numbers together, and all the variables

-4X^2-28X-48

Back to the equation:

-(-4X^2-28X-48)


We get rid of parentheses

4X^2+28X+X+48=0

We add all the numbers together, and all the variables

4X^2+29X+48=0

a = 4; b = 29; c = +48;
Δ = b2-4ac
Δ = 292-4·4·48
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{73}}{2*4}=\frac{-29-\sqrt{73}}{8}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{73}}{2*4}=\frac{-29+\sqrt{73}}{8}
$