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X=-5/2X-6
We move all terms to the left:
X-(-5/2X-6)=0
Domain of the equation: 2X-6)!=0We get rid of parentheses
X∈R
X+5/2X+6=0
We multiply all the terms by the denominator
X*2X+6*2X+5=0
Wy multiply elements
2X^2+12X+5=0
a = 2; b = 12; c = +5;
Δ = b2-4ac
Δ = 122-4·2·5
Δ = 104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{104}=\sqrt{4*26}=\sqrt{4}*\sqrt{26}=2\sqrt{26}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{26}}{2*2}=\frac{-12-2\sqrt{26}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{26}}{2*2}=\frac{-12+2\sqrt{26}}{4} $
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