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X=13-1/3X
We move all terms to the left:
X-(13-1/3X)=0
Domain of the equation: 3X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(-1/3X+13)=0
We get rid of parentheses
X+1/3X-13=0
We multiply all the terms by the denominator
X*3X-13*3X+1=0
Wy multiply elements
3X^2-39X+1=0
a = 3; b = -39; c = +1;
Δ = b2-4ac
Δ = -392-4·3·1
Δ = 1509
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{1509}}{2*3}=\frac{39-\sqrt{1509}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{1509}}{2*3}=\frac{39+\sqrt{1509}}{6} $
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