X=2+(y.y.y)=22

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Solution for X=2+(y.y.y)=22 equation: 



X=2+(X.X.X)=22

We move all terms to the left:

X-(2+(X.X.X))=0

We add all the numbers together, and all the variables

X-(2+(+X.X.X))=0



We calculate terms in parentheses: -(2+(+X.X.X)), so:

2+(+X.X.X)

determiningTheFunctionDomain
(+X.X.X)+2

We get rid of parentheses

X.X.X+2

Back to the equation:

-(X.X.X+2)



We get rid of parentheses

X-X.X.X-2=0

We move all terms containing X to the left, all other terms to the right

X-X.X.X=2

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