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X=2/5X+7
We move all terms to the left:
X-(2/5X+7)=0
Domain of the equation: 5X+7)!=0We get rid of parentheses
X∈R
X-2/5X-7=0
We multiply all the terms by the denominator
X*5X-7*5X-2=0
Wy multiply elements
5X^2-35X-2=0
a = 5; b = -35; c = -2;
Δ = b2-4ac
Δ = -352-4·5·(-2)
Δ = 1265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1265}}{2*5}=\frac{35-\sqrt{1265}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1265}}{2*5}=\frac{35+\sqrt{1265}}{10} $
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