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X=26X^2-14X
We move all terms to the left:
X-(26X^2-14X)=0
We get rid of parentheses
-26X^2+X+14X=0
We add all the numbers together, and all the variables
-26X^2+15X=0
a = -26; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-26)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-26}=\frac{-30}{-52} =15/26 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-26}=\frac{0}{-52} =0 $
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