X=3(2x+4)=2+6x+10

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Solution for X=3(2x+4)=2+6x+10 equation: 



X=3(2X+4)=2+6X+10

We move all terms to the left:

X-(3(2X+4))=0



We calculate terms in parentheses: -(3(2X+4)), so:

3(2X+4)

We multiply parentheses

6X+12

Back to the equation:

-(6X+12)



We get rid of parentheses

X-6X-12=0

We add all the numbers together, and all the variables

-5X-12=0

We move all terms containing X to the left, all other terms to the right

-5X=12

X=12/-5

X=-2+2/5

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