X=3,3x2-21/3x

Solution for X=3,3x2-21/3x equation:

X=3.3X^2-21/3X

We move all terms to the left:

X-(3.3X^2-21/3X)=0


Domain of the equation: 3X)!=0

X!=0/1

X!=0

X∈R


We get rid of parentheses

-3.3X^2+X+21/3X=0

We multiply all the terms by the denominator


-(3.3X^2)*3X+X*3X+21=0

We multiply parentheses

-9X^2+X*3X+21=0

Wy multiply elements

-9X^2+3X^2+21=0

We add all the numbers together, and all the variables

-6X^2+21=0

a = -6; b = 0; c = +21;
Δ = b2-4ac
Δ = 02-4·(-6)·21
Δ = 504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{504}=\sqrt{36*14}=\sqrt{36}*\sqrt{14}=6\sqrt{14}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{14}}{2*-6}=\frac{0-6\sqrt{14}}{-12}
=-\frac{6\sqrt{14}}{-12}
=-\frac{\sqrt{14}}{-2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{14}}{2*-6}=\frac{0+6\sqrt{14}}{-12}
=\frac{6\sqrt{14}}{-12}
=\frac{\sqrt{14}}{-2}
$