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X=3/2X
We move all terms to the left:
X-(3/2X)=0
Domain of the equation: 2X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+3/2X)=0
We get rid of parentheses
X-3/2X=0
We multiply all the terms by the denominator
X*2X-3=0
Wy multiply elements
2X^2-3=0
a = 2; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·2·(-3)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{6}}{2*2}=\frac{0-2\sqrt{6}}{4} =-\frac{2\sqrt{6}}{4} =-\frac{\sqrt{6}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{6}}{2*2}=\frac{0+2\sqrt{6}}{4} =\frac{2\sqrt{6}}{4} =\frac{\sqrt{6}}{2} $
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