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X=3/5X+8
We move all terms to the left:
X-(3/5X+8)=0
Domain of the equation: 5X+8)!=0We get rid of parentheses
X∈R
X-3/5X-8=0
We multiply all the terms by the denominator
X*5X-8*5X-3=0
Wy multiply elements
5X^2-40X-3=0
a = 5; b = -40; c = -3;
Δ = b2-4ac
Δ = -402-4·5·(-3)
Δ = 1660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1660}=\sqrt{4*415}=\sqrt{4}*\sqrt{415}=2\sqrt{415}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-2\sqrt{415}}{2*5}=\frac{40-2\sqrt{415}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+2\sqrt{415}}{2*5}=\frac{40+2\sqrt{415}}{10} $
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