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X=4+9/2X
We move all terms to the left:
X-(4+9/2X)=0
Domain of the equation: 2X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(9/2X+4)=0
We get rid of parentheses
X-9/2X-4=0
We multiply all the terms by the denominator
X*2X-4*2X-9=0
Wy multiply elements
2X^2-8X-9=0
a = 2; b = -8; c = -9;
Δ = b2-4ac
Δ = -82-4·2·(-9)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{34}}{2*2}=\frac{8-2\sqrt{34}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{34}}{2*2}=\frac{8+2\sqrt{34}}{4} $
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