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X=4X-3/2X
We move all terms to the left:
X-(4X-3/2X)=0
Domain of the equation: 2X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+4X-3/2X)=0
We get rid of parentheses
X-4X+3/2X=0
We multiply all the terms by the denominator
X*2X-4X*2X+3=0
Wy multiply elements
2X^2-8X^2+3=0
We add all the numbers together, and all the variables
-6X^2+3=0
a = -6; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-6)·3
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{2}}{2*-6}=\frac{0-6\sqrt{2}}{-12} =-\frac{6\sqrt{2}}{-12} =-\frac{\sqrt{2}}{-2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{2}}{2*-6}=\frac{0+6\sqrt{2}}{-12} =\frac{6\sqrt{2}}{-12} =\frac{\sqrt{2}}{-2} $
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