X=4x(3x+40)

Solution for X=4x(3x+40) equation:

X=4X(3X+40)

We move all terms to the left:

X-(4X(3X+40))=0


We calculate terms in parentheses: -(4X(3X+40)), so:

4X(3X+40)

We multiply parentheses

12X^2+160X

Back to the equation:

-(12X^2+160X)


We get rid of parentheses

-12X^2+X-160X=0

We add all the numbers together, and all the variables

-12X^2-159X=0

a = -12; b = -159; c = 0;
Δ = b2-4ac
Δ = -1592-4·(-12)·0
Δ = 25281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25281}=159$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-159)-159}{2*-12}=\frac{0}{-24}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-159)+159}{2*-12}=\frac{318}{-24}
=-13+1/4
$