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X=5/3X-10
We move all terms to the left:
X-(5/3X-10)=0
Domain of the equation: 3X-10)!=0We get rid of parentheses
X∈R
X-5/3X+10=0
We multiply all the terms by the denominator
X*3X+10*3X-5=0
Wy multiply elements
3X^2+30X-5=0
a = 3; b = 30; c = -5;
Δ = b2-4ac
Δ = 302-4·3·(-5)
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-8\sqrt{15}}{2*3}=\frac{-30-8\sqrt{15}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+8\sqrt{15}}{2*3}=\frac{-30+8\sqrt{15}}{6} $
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