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X=6+2/3X
We move all terms to the left:
X-(6+2/3X)=0
Domain of the equation: 3X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(2/3X+6)=0
We get rid of parentheses
X-2/3X-6=0
We multiply all the terms by the denominator
X*3X-6*3X-2=0
Wy multiply elements
3X^2-18X-2=0
a = 3; b = -18; c = -2;
Δ = b2-4ac
Δ = -182-4·3·(-2)
Δ = 348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{348}=\sqrt{4*87}=\sqrt{4}*\sqrt{87}=2\sqrt{87}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{87}}{2*3}=\frac{18-2\sqrt{87}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{87}}{2*3}=\frac{18+2\sqrt{87}}{6} $
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