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X=7/2X-8
We move all terms to the left:
X-(7/2X-8)=0
Domain of the equation: 2X-8)!=0We get rid of parentheses
X∈R
X-7/2X+8=0
We multiply all the terms by the denominator
X*2X+8*2X-7=0
Wy multiply elements
2X^2+16X-7=0
a = 2; b = 16; c = -7;
Δ = b2-4ac
Δ = 162-4·2·(-7)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{78}}{2*2}=\frac{-16-2\sqrt{78}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{78}}{2*2}=\frac{-16+2\sqrt{78}}{4} $
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