X=8(2x+4-x+3)x+3

Solution for X=8(2x+4-x+3)x+3 equation:

X=8(2X+4-X+3)X+3

We move all terms to the left:

X-(8(2X+4-X+3)X+3)=0

We add all the numbers together, and all the variables

X-(8(X+7)X+3)=0


We calculate terms in parentheses: -(8(X+7)X+3), so:

8(X+7)X+3

We multiply parentheses

8X^2+56X+3

Back to the equation:

-(8X^2+56X+3)


We get rid of parentheses

-8X^2+X-56X-3=0

We add all the numbers together, and all the variables

-8X^2-55X-3=0

a = -8; b = -55; c = -3;
Δ = b2-4ac
Δ = -552-4·(-8)·(-3)
Δ = 2929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{2929}}{2*-8}=\frac{55-\sqrt{2929}}{-16}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{2929}}{2*-8}=\frac{55+\sqrt{2929}}{-16}
$