X=9/5*x+32

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Solution for X=9/5*x+32 equation:



X=9/5X+32
We move all terms to the left:
X-(9/5X+32)=0
Domain of the equation: 5X+32)!=0
X∈R
We get rid of parentheses
X-9/5X-32=0
We multiply all the terms by the denominator
X*5X-32*5X-9=0
Wy multiply elements
5X^2-160X-9=0
a = 5; b = -160; c = -9;
Δ = b2-4ac
Δ = -1602-4·5·(-9)
Δ = 25780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{25780}=\sqrt{4*6445}=\sqrt{4}*\sqrt{6445}=2\sqrt{6445}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-2\sqrt{6445}}{2*5}=\frac{160-2\sqrt{6445}}{10} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+2\sqrt{6445}}{2*5}=\frac{160+2\sqrt{6445}}{10} $

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