If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X=9/5X+32
We move all terms to the left:
X-(9/5X+32)=0
Domain of the equation: 5X+32)!=0We get rid of parentheses
X∈R
X-9/5X-32=0
We multiply all the terms by the denominator
X*5X-32*5X-9=0
Wy multiply elements
5X^2-160X-9=0
a = 5; b = -160; c = -9;
Δ = b2-4ac
Δ = -1602-4·5·(-9)
Δ = 25780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25780}=\sqrt{4*6445}=\sqrt{4}*\sqrt{6445}=2\sqrt{6445}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-2\sqrt{6445}}{2*5}=\frac{160-2\sqrt{6445}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+2\sqrt{6445}}{2*5}=\frac{160+2\sqrt{6445}}{10} $
| 0.01x=20 | | 5-3x-8+2x=21-9 | | 5(4x-3)-2(2x+1)=15 | | 20=5x^2-5x | | 4x+-6=2(x+3) | | (6x+15)=x | | 343^3x=1000 | | ((1200)/(25x))=((25x)/(25+2x))^((2)/(3)) | | 4(5x+1)=-2 | | 4p^2–9p+4=0 | | 3(4x=1)=123 | | X/4+5=x/3+10 | | 9x+1=6(x+1~) | | X^2=0.04x+18^2 | | x÷4=6 | | 0=2x-25000/x^2 | | 7(3x+5)=120 | | C=50h+80 | | C=50h+8 | | C=50h-8 | | x+0,2x=15 | | x-x*0.2=640 | | 3(2x–1)+2x=21 | | 800-800*0.2=x | | 4x^2+2x-2=6 | | 800(800-0.2)=x | | 800*800-0.2=x | | x(x-0.2)=640 | | 2+3x=28 | | 2(8+x)=3 | | x*x-0.2=640 | | 1/2*x/4+2x/3=x+1 |