X=9;x2-14

Solution for X=9;x2-14 equation:

X=9X^2-14

We move all terms to the left:

X-(9X^2-14)=0

We get rid of parentheses

-9X^2+X+14=0

a = -9; b = 1; c = +14;
Δ = b2-4ac
Δ = 12-4·(-9)·14
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{505}}{2*-9}=\frac{-1-\sqrt{505}}{-18}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{505}}{2*-9}=\frac{-1+\sqrt{505}}{-18}
$