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X=X/3X+6
We move all terms to the left:
X-(X/3X+6)=0
Domain of the equation: 3X+6)!=0We get rid of parentheses
X∈R
X-X/3X-6=0
We multiply all the terms by the denominator
X*3X-X-6*3X=0
We add all the numbers together, and all the variables
-1X+X*3X-6*3X=0
Wy multiply elements
3X^2-1X-18X=0
We add all the numbers together, and all the variables
3X^2-19X=0
a = 3; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·3·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*3}=\frac{0}{6} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*3}=\frac{38}{6} =6+1/3 $
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