Xx4-68=3x(x+4)

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Solution for Xx4-68=3x(x+4) equation: 



XX4-68=3X(X+4)

We move all terms to the left:

XX4-68-(3X(X+4))=0



We calculate terms in parentheses: -(3X(X+4)), so:

3X(X+4)

We multiply parentheses

3X^2+12X

Back to the equation:

-(3X^2+12X)



We get rid of parentheses

-3X^2+XX4-12X-68=0

We add all the numbers together, and all the variables

-3X^2-12X+XX4-68=0

We move all terms containing X to the left, all other terms to the right

-3X^2-12X+XX4=68

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