Y(4y-1)=2(5y+1/2)

Solution for Y(4y-1)=2(5y+1/2) equation:

(4Y-1)=2(5Y+1/2)

We move all terms to the left:

(4Y-1)-(2(5Y+1/2))=0

We add all the numbers together, and all the variables

(4Y-1)-(2(+5Y+1/2))=0

We get rid of parentheses

4Y-(2(+5Y+1/2))-1=0

We multiply all the terms by the denominator


4Y*2))-(2(+5Y+1-1*2))=0

We add all the numbers together, and all the variables

4Y*2))-(2(5Y-1))=0

We add all the numbers together, and all the variables

4Y*2))-(2(5Y=0

Wy multiply elements

8Y^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{0}{16}=0$