Y(x)=x2+2

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Solution for Y(x)=x2+2 equation: 



(Y)=Y2+2

We move all terms to the left:

(Y)-(Y2+2)=0

We add all the numbers together, and all the variables

-(+Y^2+2)+Y=0

We get rid of parentheses

-Y^2+Y-2=0

We add all the numbers together, and all the variables

-1Y^2+Y-2=0

a = -1; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·(-1)·(-2)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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