Y+1=2/3(x-12)

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Solution for Y+1=2/3(x-12) equation:



+1=2/3(Y-12)
We move all terms to the left:
+1-(2/3(Y-12))=0
Domain of the equation: 3(Y-12))!=0
Y∈R
We multiply all the terms by the denominator
-(2+1*3(Y-12))=0
We calculate terms in parentheses: -(2+1*3(Y-12)), so:
2+1*3(Y-12)
determiningTheFunctionDomain 1*3(Y-12)+2
Wy multiply elements
3Y(Y+2
Back to the equation:
-(3Y(Y+2)
We calculate terms in parentheses: -(3Y(Y+2), so:
3Y(Y+2
We calculate terms in parentheses: -(3Y(Y+2), so:
3Y(Y+2
We calculate terms in parentheses: -(3Y(Y+2), so:
3Y(Y+2
We calculate terms in parentheses: -(3Y(Y+2), so:
3Y(Y+2
We calculate terms in parentheses: -(3Y(Y+2), so:
3Y(Y+2
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3Y(Y+2
We calculate terms in parentheses: -(3Y(Y+2), so:
3Y(Y+2
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3Y(Y+2
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3Y(Y+2
We calculate terms in parentheses: -(3Y(Y+2), so:
3Y(Y+2
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3Y(Y+2
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3Y(Y+2
We calculate terms in parentheses: -(3Y(Y+2), so:
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