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+1=2/3(Y-8)
We move all terms to the left:
+1-(2/3(Y-8))=0
Domain of the equation: 3(Y-8))!=0We multiply all the terms by the denominator
Y∈R
-(2+1*3(Y-8))=0
We calculate terms in parentheses: -(2+1*3(Y-8)), so:
2+1*3(Y-8)
determiningTheFunctionDomain 1*3(Y-8)+2
Wy multiply elements
3Y(Y+2
Back to the equation:
-(3Y(Y+2)
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