Y+1=3y-5(y-2)

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Solution for Y+1=3y-5(y-2) equation: 



+1=3Y-5(Y-2)

We move all terms to the left:

+1-(3Y-5(Y-2))=0



We calculate terms in parentheses: -(3Y-5(Y-2)), so:

3Y-5(Y-2)

We multiply parentheses

3Y-5Y+10

We add all the numbers together, and all the variables

-2Y+10

Back to the equation:

-(-2Y+10)



We get rid of parentheses

2Y-10+1=0

We add all the numbers together, and all the variables

2Y-9=0

We move all terms containing Y to the left, all other terms to the right

2Y=9

Y=9/2

Y=4+1/2

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