Y+2=-1/3(x-2)(-2,-3)

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Solution for Y+2=-1/3(x-2)(-2,-3) equation: 



+2=-1/3(Y-2)(-2.-3)

We move all terms to the left:

+2-(-1/3(Y-2)(-2.-3))=0



Domain of the equation: 3(Y-2)(-2.-3))!=0

Y∈R



We add all the numbers together, and all the variables

-(-1/3(Y-2)(-5))+2=0

We multiply parentheses ..

-(-1/3(-5Y+10))+2=0

We multiply all the terms by the denominator


-(-1+2*3(-5Y+10))=0



We calculate terms in parentheses: -(-1+2*3(-5Y+10)), so:

-1+2*3(-5Y+10)

determiningTheFunctionDomain
2*3(-5Y+10)-1

Wy multiply elements

6Y(--1

We use the square of the difference formula

6Y(+1

Back to the equation:

-(6Y(+1)



We add all the numbers together, and all the variables

-(6Y1=0

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