Y+2=3/2(x+2)

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Solution for Y+2=3/2(x+2) equation:



+2=3/2(Y+2)
We move all terms to the left:
+2-(3/2(Y+2))=0
Domain of the equation: 2(Y+2))!=0
Y∈R
We multiply all the terms by the denominator
-(3+2*2(Y+2))=0
We calculate terms in parentheses: -(3+2*2(Y+2)), so:
3+2*2(Y+2)
determiningTheFunctionDomain 2*2(Y+2)+3
Wy multiply elements
4Y(Y+3
Back to the equation:
-(4Y(Y+3)
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3
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4Y(Y+3
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We calculate terms in parentheses: -(4Y(Y+3), so:
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
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4Y(Y+3
We calculate terms in parentheses: -(4Y(Y+3), so:
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We calculate terms in parentheses: -(4Y(Y+3), so:
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We calculate terms in parentheses: -(4Y(Y+3), so:
4Y(Y+3

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