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+3=3/2(Y+1)
We move all terms to the left:
+3-(3/2(Y+1))=0
Domain of the equation: 2(Y+1))!=0We multiply all the terms by the denominator
Y∈R
-(3+3*2(Y+1))=0
We calculate terms in parentheses: -(3+3*2(Y+1)), so:
3+3*2(Y+1)
determiningTheFunctionDomain 3*2(Y+1)+3
Wy multiply elements
6Y(Y+3
Back to the equation:
-(6Y(Y+3)
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| 216=3y+y | | 183=61-x | | 8)-7(x+3)=-4(x-6) | | 29+4q=81 | | -85+-5x+11x=47 | | 6x+9=-7x-134 | | y2-12y=-27 | | t/5+42=51 | | 5x+4=7x+28 | | y=3/4=21/2 | | 19=a7.2 | | 22-u=166 | | 33x-6)=18 | | 54+86+128+x=360 | | 10y^2+49y-9=0 | | 3k^2+17k+14=0 | | 5)-(n-7)-n=-8(6+n)+6n | | 3+5n=5(n+2)-4 | | 5/6e-2/3e=-24 | | 6-5x=-2x+27 | | x−12÷6=9 | | f(9)=–3(9)+2 | | 6x+1=25+4x | | 3(3+6x)=-189 | | 6(7+x)=48 | | 4=u/5-1 | | 7(-3u-4)+10u=-7u+12 | | 12u-7=15u+11 | | 54n=109 | | v/6+6.1=-13.1 | | 40+96+113+x=360 | | 4(-2x+5)=100 |