Y+4=(-11/2)(x-4)

Solution for Y+4=(-11/2)(x-4) equation:

+4=(-11/2)(Y-4)

We move all terms to the left:

+4-((-11/2)(Y-4))=0


Domain of the equation: 2)(Y-4))!=0

Y∈R


We multiply parentheses ..

-((-11Y^2-11/2*-4))+4=0

We multiply all the terms by the denominator


-((-11Y^2-11+4*2*-4))=0


We calculate terms in parentheses: -((-11Y^2-11+4*2*-4)), so:

(-11Y^2-11+4*2*-4)

We get rid of parentheses

-11Y^2-11-4+4*2*

We add all the numbers together, and all the variables

-11Y^2

Back to the equation:

-(-11Y^2)


We get rid of parentheses

11Y^2=0

a = 11; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·11·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{0}{22}=0$