Y+4=(3/5)(x+9)

Solution for Y+4=(3/5)(x+9) equation:

+4=(3/5)(Y+9)

We move all terms to the left:

+4-((3/5)(Y+9))=0


Domain of the equation: 5)(Y+9))!=0

Y∈R


We add all the numbers together, and all the variables

-((+3/5)(Y+9))+4=0

We multiply parentheses ..

-((+3Y^2+3/5*9))+4=0

We multiply all the terms by the denominator


-((+3Y^2+3+4*5*9))=0


We calculate terms in parentheses: -((+3Y^2+3+4*5*9)), so:

(+3Y^2+3+4*5*9)

We get rid of parentheses

3Y^2+3+4*5*9

We add all the numbers together, and all the variables

3Y^2+183

Back to the equation:

-(3Y^2+183)


We get rid of parentheses

-3Y^2-183=0

a = -3; b = 0; c = -183;
Δ = b2-4ac
Δ = 02-4·(-3)·(-183)
Δ = -2196
Delta is less than zero, so there is no solution for the equation