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+4=-5/2(Y-3)
We move all terms to the left:
+4-(-5/2(Y-3))=0
Domain of the equation: 2(Y-3))!=0We multiply all the terms by the denominator
Y∈R
-(-5+4*2(Y-3))=0
We calculate terms in parentheses: -(-5+4*2(Y-3)), so:
-5+4*2(Y-3)
determiningTheFunctionDomain 4*2(Y-3)-5
Wy multiply elements
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Back to the equation:
-(8Y(Y-5)
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| 7)9(x+2)-4=2(90+7) | | (5)+y=8 | | 2x+7+3x=40x= | | 5x+x6x+-6=5 | | 4h-2h+h=6 | | -15(11/3k+113/8)+1/6=-9809/96 | | .65=(x-20)/x | | -8x-32=3x-153 | | (16)=x-13 | | 42-8x=12+8x | | 16c-11c+5c-5c=20 | | 5x+6+-6=5 | | 0.00000381469x=1 | | 114x=48 | | 1.9x+12.8=24.58 | | 110=-34+9x | | -5.2z=-41.6 | | (X+15)x=32 | | 110=-34-9x | | -4n-5=-3n+44 | | 7c+4(c+3)=34 | | (X+15)x=33 | | 5/2=8/3r-4 | | 12x-24=11x-35 | | 5=10c+4c | | 8+7(4n+8)=176 | | 9x-3+2x+20=15+4x1-2+7x | | 9c=4+2 | | 11314a=157 | | (1/3)|4x+2x-1=4 | | -83=5-8(n+3) | | 11-10=8-v |