Y+4=2/2y-3=5

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Solution for Y+4=2/2y-3=5 equation:



+4=2/2Y-3=5
We move all terms to the left:
+4-(2/2Y-3)=0
Domain of the equation: 2Y-3)!=0
Y∈R
We get rid of parentheses
-2/2Y+3+4=0
We multiply all the terms by the denominator
3*2Y+4*2Y-2=0
Wy multiply elements
6Y+8Y-2=0
We add all the numbers together, and all the variables
14Y-2=0
We move all terms containing Y to the left, all other terms to the right
14Y=2
Y=2/14
Y=1/7

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