Y+4=2y+3(y-4)

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Solution for Y+4=2y+3(y-4) equation: 



+4=2Y+3(Y-4)

We move all terms to the left:

+4-(2Y+3(Y-4))=0



We calculate terms in parentheses: -(2Y+3(Y-4)), so:

2Y+3(Y-4)

We multiply parentheses

2Y+3Y-12

We add all the numbers together, and all the variables

5Y-12

Back to the equation:

-(5Y-12)



We get rid of parentheses

-5Y+12+4=0

We add all the numbers together, and all the variables

-5Y+16=0

We move all terms containing Y to the left, all other terms to the right

-5Y=-16

Y=-16/-5

Y=3+1/5

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