Y-(-10)=(-9/11)(x-3)

Solution for Y-(-10)=(-9/11)(x-3) equation:

-(-10)=(-9/11)(Y-3)

We move all terms to the left:

-(-10)-((-9/11)(Y-3))=0


Domain of the equation: 11)(Y-3))!=0

Y∈R


We add all the numbers together, and all the variables

-((-9/11)(Y-3))+10=0

We multiply parentheses ..

-((-9Y^2-9/11*-3))+10=0

We multiply all the terms by the denominator


-((-9Y^2-9+10*11*-3))=0


We calculate terms in parentheses: -((-9Y^2-9+10*11*-3)), so:

(-9Y^2-9+10*11*-3)

We get rid of parentheses

-9Y^2-9-3+10*11*

We add all the numbers together, and all the variables

-9Y^2

Back to the equation:

-(-9Y^2)


We get rid of parentheses

9Y^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{0}{18}=0$