Y-1=-1/4(x-3)2

Solution for Y-1=-1/4(x-3)2 equation:

x in (-oo:+oo)

Y-1 = (-1/4)*(x-3)^2 // - (-1/4)*(x-3)^2

Y-((-1/4)*(x-3)^2)-1 = 0

(1/4)*(x-3)^2+Y-1 = 0

1/4*(x-3)^2+Y-1 = 0

1/4*(x-3)^2+Y-1 = 0

Y+1/4*x^2-3/2*x-1+9/4 = 0

Y+1/4*x^2-3/2*x+5/4 = 0

Y+1/4*x^2-3/2*x+5/4 = 0

Y+1/4*x^2-3/2*x+5/4 = 0

DELTA = (-3/2)^2-(1/4*4*(Y+5/4))

DELTA = 1-Y

1-Y = 0

1-Y = 0 // - 1

-Y = -1 // * -1

Y = 1

DELTA = 0  <=>  t_3 = 1

x = 3/2/(1/4*2) i Y = 1

x = 3 i Y = 1

( x = ((1-Y)^(1/2)+3/2)/(1/4*2) or x = (3/2-(1-Y)^(1/2))/(1/4*2) ) i Y > 1

( x = 2*((1-Y)^(1/2)+3/2) or x = 2*(3/2-(1-Y)^(1/2)) ) i Y > 1

Y-1 > 0

Y-1 > 0 // + 1

Y > 1

x in { 3, 2*((1-Y)^(1/2)+3/2), 2*(3/2-(1-Y)^(1/2)) }