Y-1=2/3(x+3)

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Solution for Y-1=2/3(x+3) equation:



-1=2/3(Y+3)
We move all terms to the left:
-1-(2/3(Y+3))=0
Domain of the equation: 3(Y+3))!=0
Y∈R
We multiply all the terms by the denominator
-(2-1*3(Y+3))=0
We calculate terms in parentheses: -(2-1*3(Y+3)), so:
2-1*3(Y+3)
determiningTheFunctionDomain -1*3(Y+3)+2
Wy multiply elements
-3Y(Y+2
Back to the equation:
-(-3Y(Y+2)
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
We calculate terms in parentheses: -(-3Y(Y+2), so:
-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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-3Y(Y+2
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