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-1=2/5(Y-5)
We move all terms to the left:
-1-(2/5(Y-5))=0
Domain of the equation: 5(Y-5))!=0We multiply all the terms by the denominator
Y∈R
-(2-1*5(Y-5))=0
We calculate terms in parentheses: -(2-1*5(Y-5)), so:
2-1*5(Y-5)
determiningTheFunctionDomain -1*5(Y-5)+2
Wy multiply elements
-5Y(Y+2
Back to the equation:
-(-5Y(Y+2)
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-5Y(Y+2
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| -9(m+3)+14=49 | | y-y/4=60 | | −6x2+6x+120=0 | | 150=-5n | | 36=+2n | | 38=3+5p | | 160-4x=x | | 12x2+8x=20 | | 3/7a=6 | | x/0.05=0.05 | | b) 2(5X-2)+3(1-X)=13 | | H=-16t2+18t+5 | | 14+2x+6=4x-15-7x | | k-1/4=-2 | | 3^5x=9^x+3 | | k/3=15/05 | | x-28=-28 | | 6−5z=−34 | | 3(x+11)=0 | | 7x+3=75+x=6 | | x^2+x-1900=0 | | 5 | | Y=3(1.61)^t | | 3(2-6x)=4(4x-0.5)-2x | | x²+4x-100=0 | | ( | | 2x+(x+5)=-x-11 | | 3(2x-4)-2x=-8 | | (2x+5)(3x-1)+(3x-4)(2-3x)=-3x2+28x+17 | | | | 8x+4=-2x+64 | | |