Y-2=1/5(3x+3)

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Solution for Y-2=1/5(3x+3) equation: 



-2=1/5(3Y+3)

We move all terms to the left:

-2-(1/5(3Y+3))=0



Domain of the equation: 5(3Y+3))!=0

Y∈R



We multiply all the terms by the denominator


-(1-2*5(3Y+3))=0



We calculate terms in parentheses: -(1-2*5(3Y+3)), so:

1-2*5(3Y+3)

determiningTheFunctionDomain
-2*5(3Y+3)+1

Wy multiply elements

-10Y(3+1

Back to the equation:

-(-10Y(3+1)



We add all the numbers together, and all the variables

-(-10Y4=0

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