Y-3=-1/5(x+2);(-2,7)

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Solution for Y-3=-1/5(x+2);(-2,7) equation: 



-3=-1/5(Y+2)(-2.7)

We move all terms to the left:

-3-(-1/5(Y+2)(-2.7))=0



Domain of the equation: 5(Y+2)(-2.7))!=0

Y∈R



We multiply parentheses ..

-(-1/5(-2.7Y-5.4))-3=0

We multiply all the terms by the denominator


-(-1-3*5(-2.7Y-5.4))=0



We calculate terms in parentheses: -(-1-3*5(-2.7Y-5.4)), so:

-1-3*5(-2.7Y-5.4)

determiningTheFunctionDomain
-3*5(-2.7Y-5.4)-1

Wy multiply elements

-15Y(--1

We use the square of the difference formula

-15Y(+1

Back to the equation:

-(-15Y(+1)



We add all the numbers together, and all the variables

-(-15Y1=0

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