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-3=2/3(Y+5)
We move all terms to the left:
-3-(2/3(Y+5))=0
Domain of the equation: 3(Y+5))!=0We multiply all the terms by the denominator
Y∈R
-(2-3*3(Y+5))=0
We calculate terms in parentheses: -(2-3*3(Y+5)), so:
2-3*3(Y+5)
determiningTheFunctionDomain -3*3(Y+5)+2
Wy multiply elements
-9Y(Y+2
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-(-9Y(Y+2)
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| 33.2b*5=10.76 | | 14+3h=4h | | 2c+2c+2c=180 | | b-35+46+37=180 | | z+40+4z+9z=180 | | 3.2b+5=10.75 | | c-39+41+79=180 | | 45+3v+2v=180 | | 5x+4x+63=180 | | 35+85+5v=180 | | 50+3z+2z=180 | | 4(1/2+3=3x+12-x | | 100+30+10x=180 | | 35+39+2x=180 | | 2x(1/3x-5)=2 | | (7+x)/3=2x+5 | | 3(x-6=) | | 1/5c+9=-19 | | -30=5(8v-6) | | `6(1+2x)-6x=-3(-8x+4)` | | 9+14x‒8x= | | 544/36x=14 | | -27=r.12-19 | | 15=-7+r.3 | | 0,75x=1 | | 60+10y=-20 | | 6x^2+16x-35=0 | | 9,60=x·0,150 | | -5(-5u+4)-4u=3(u-8)-8 | | -5x=-8.5 | | y-(-15)=-20 | | 0.4x+0.1=0.6x-0.7 |