Y-3=2/5(x+1)

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Solution for Y-3=2/5(x+1) equation:



-3=2/5(Y+1)
We move all terms to the left:
-3-(2/5(Y+1))=0
Domain of the equation: 5(Y+1))!=0
Y∈R
We multiply all the terms by the denominator
-(2-3*5(Y+1))=0
We calculate terms in parentheses: -(2-3*5(Y+1)), so:
2-3*5(Y+1)
determiningTheFunctionDomain -3*5(Y+1)+2
Wy multiply elements
-15Y(Y+2
Back to the equation:
-(-15Y(Y+2)
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
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-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
We calculate terms in parentheses: -(-15Y(Y+2), so:
-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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-15Y(Y+2
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