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-5=1/2(Y+4)
We move all terms to the left:
-5-(1/2(Y+4))=0
Domain of the equation: 2(Y+4))!=0We multiply all the terms by the denominator
Y∈R
-(1-5*2(Y+4))=0
We calculate terms in parentheses: -(1-5*2(Y+4)), so:
1-5*2(Y+4)
determiningTheFunctionDomain -5*2(Y+4)+1
Wy multiply elements
-10Y(Y+1
Back to the equation:
-(-10Y(Y+1)
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| 3x+25=2(3x-10) | | -13x+39=-4x+5 | | 12n-25=35 | | k/4+12=20 | | 4(x-3)+6=(2x-6) | | 6(2x-18)=210 | | 6+x/4=18 | | 87=5y-8 | | m/6-9=17 | | 6x+2x+3=77 | | -4x1=25 | | 5(x+7)+3=-7(x3-)-10 | | (9+k)^3+(12-7)^2=9 | | 6x+6=5(x+1)-5 | | (2x)+(3x)=180 | | 8x+3=47 | | 3b-6=b/2+1/4 | | 0.2x=9.8 | | -4/9=w-4 | | )4+2p=10(53 p−2) | | 13+8=-3(9x-7) | | 9-4(3x+1)=3(6-3x)9 | | 62−21 n=3n+16 | | 2+-s=-2 | | 3x+1=2x–2 | | X=16-1/20y | | 8x+8=7x-4 | | 8.7x=139.2 | | a/3=4a-33 | | 9(x+5)+2=-9(x-6)-10 | | 435/8=x | | 15x+3x-11=10-x-16-5x |