Y-5=2(x-3)+5

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Solution for Y-5=2(x-3)+5 equation:



-5=2(Y-3)+5
We move all terms to the left:
-5-(2(Y-3)+5)=0
We calculate terms in parentheses: -(2(Y-3)+5), so:
2(Y-3)+5
We multiply parentheses
2Y-6+5
We add all the numbers together, and all the variables
2Y-1
Back to the equation:
-(2Y-1)
We get rid of parentheses
-2Y+1-5=0
We add all the numbers together, and all the variables
-2Y-4=0
We move all terms containing Y to the left, all other terms to the right
-2Y=4
Y=4/-2
Y=-2

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