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-6=4/5(Y+2)
We move all terms to the left:
-6-(4/5(Y+2))=0
Domain of the equation: 5(Y+2))!=0We multiply all the terms by the denominator
Y∈R
-(4-6*5(Y+2))=0
We calculate terms in parentheses: -(4-6*5(Y+2)), so:
4-6*5(Y+2)
determiningTheFunctionDomain -6*5(Y+2)+4
Wy multiply elements
-30Y(Y+4
Back to the equation:
-(-30Y(Y+4)
We calculate terms in parentheses: -(-30Y(Y+4), so:
-30Y(Y+4
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