Y2-5/3y=25/36

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Solution for Y2-5/3y=25/36 equation: 



2-5/3Y=25/36

We move all terms to the left:

2-5/3Y-(25/36)=0



Domain of the equation: 3Y!=0

Y!=0/3

Y!=0

Y∈R



We add all the numbers together, and all the variables

-5/3Y+2-(+25/36)=0

We get rid of parentheses

-5/3Y+2-25/36=0

We calculate fractions

There is no solution for this equation

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