Y3(2+10)=6x+15

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Solution for Y3(2+10)=6x+15 equation:



3(2+10)=6Y+15
We move all terms to the left:
3(2+10)-(6Y+15)=0
We add all the numbers together, and all the variables
-(6Y+15)+312=0
We get rid of parentheses
-6Y-15+312=0
We add all the numbers together, and all the variables
-6Y+297=0
We move all terms containing Y to the left, all other terms to the right
-6Y=-297
Y=-297/-6
Y=49+1/2

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