Y3-2y2+.56=0

Solution for Y3-2y2+.56=0 equation:

3-2Y^2+.56=0

We add all the numbers together, and all the variables

-2Y^2+3.56=0

a = -2; b = 0; c = +3.56;
Δ = b2-4ac
Δ = 02-4·(-2)·3.56
Δ = 28.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{28.48}}{2*-2}=\frac{0-\sqrt{28.48}}{-4}
=-\frac{\sqrt{}}{-4}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{28.48}}{2*-2}=\frac{0+\sqrt{28.48}}{-4}
=\frac{\sqrt{}}{-4}
$