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=(-7Y-7)(-5Y+5)
We move all terms to the left:
-((-7Y-7)(-5Y+5))=0
We multiply parentheses ..
-((+35Y^2-35Y+35Y-35))=0
We calculate terms in parentheses: -((+35Y^2-35Y+35Y-35)), so:We get rid of parentheses
(+35Y^2-35Y+35Y-35)
We get rid of parentheses
35Y^2-35Y+35Y-35
We add all the numbers together, and all the variables
35Y^2-35
Back to the equation:
-(35Y^2-35)
-35Y^2+35=0
a = -35; b = 0; c = +35;
Δ = b2-4ac
Δ = 02-4·(-35)·35
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70}{2*-35}=\frac{-70}{-70} =1 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70}{2*-35}=\frac{70}{-70} =-1 $
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